(3a/a^2-49)-(3/a+7)=(1/a-7)

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Solution for (3a/a^2-49)-(3/a+7)=(1/a-7) equation: 



(3a/a^2-49)-(3/a+7)=(1/a-7)

We move all terms to the left:

(3a/a^2-49)-(3/a+7)-((1/a-7))=0



Domain of the equation: a^2-49)!=0

a∈R





Domain of the equation: a+7)!=0

a∈R





Domain of the equation: a-7))!=0

a∈R



We get rid of parentheses

3a/a^2-3/a-((1/a-7))-49-7=0

We calculate fractions

We do not support eapression: a^4

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